Quadrilaterals and Polygons

intermediate quadrilaterals polygons parallelogram trapezium geometry

Quadrilaterals (four-sided figures) and polygons show up constantly in aptitude exams. The secret here is understanding the hierarchy — a square is a special rectangle, which is a special parallelogram. Once we see these relationships, properties cascade down and we don’t need to memorize everything separately.

The Quadrilateral Family Tree

Quadrilateral Trapezium Parallelogram Kite Rectangle Rhombus Square

The key insight: as we go down the tree, each shape has all the properties of its parent PLUS some extra ones. A square has every property of a rectangle AND every property of a rhombus.

Properties of Each Quadrilateral

Parallelogram

  • Opposite sides are equal AND parallel
  • Opposite angles are equal
  • Adjacent angles are supplementary (add to 180°)
  • Diagonals bisect each other (cut each other in half)
  • Area = base × height

Rectangle (Parallelogram + all right angles)

  • All angles = 90°
  • Diagonals are equal and bisect each other
  • Area = length × breadth
  • Diagonal = √(l² + b²)

Rhombus (Parallelogram + all sides equal)

  • All sides are equal
  • Diagonals bisect each other at right angles (90°)
  • Diagonals bisect the vertex angles
  • Area = ½ × d₁ × d₂ (half the product of diagonals)

Square (Rectangle + Rhombus = everything)

  • All sides equal, all angles = 90°
  • Diagonals are equal, bisect at right angles, bisect vertex angles
  • Area = side² = ½ × diagonal²
  • Diagonal = side × √2

Trapezium (only one pair of parallel sides)

  • One pair of parallel sides (called parallel sides or bases)
  • Area = ½ × (sum of parallel sides) × height = ½(a + b) × h
  • Isosceles trapezium: non-parallel sides are equal, diagonals are equal

Kite

  • Two pairs of adjacent sides are equal
  • One diagonal bisects the other at right angles
  • Area = ½ × d₁ × d₂

Key Formulas

Key Formulas — Areas
Parallelogram: base × height
Rectangle: length × breadth
Rhombus: ½ × d₁ × d₂
Square: side² = ½ × diagonal²
Trapezium: ½ × (a + b) × h
Kite: ½ × d₁ × d₂
Diagonal Relationships
Rectangle diagonal: √(l² + b²)
Square diagonal: side × √2
Rhombus side: ½ × √(d₁² + d₂²)

Diagonal Properties Quick Reference

Shape Bisect each other Equal Perpendicular
Parallelogram
Rectangle
Rhombus
Square
Kite One bisects other

Memory trick: As we go from parallelogram to square, diagonals gain more and more properties. Rectangle adds “equal,” rhombus adds “perpendicular,” and square has both.

Polygons

A polygon is any closed figure with straight sides. Quadrilaterals are 4-sided polygons. Let’s look at the general rules.

Angle Sum of a Polygon

Interior angle sum = (n - 2) × 180°, where n is the number of sides.

This makes sense: a triangle (3 sides) has 180°, a quadrilateral (4 sides) has 360°, a pentagon has 540°, and so on. We’re basically dividing the polygon into (n-2) triangles.

Regular Polygons

A regular polygon has all sides equal AND all angles equal.

  • Each interior angle = (n - 2) × 180° / n
  • Each exterior angle = 360° / n
  • Number of diagonals = n(n - 3) / 2
Polygon Sides Angle Sum Each Interior ∠ Each Exterior ∠ Diagonals
Triangle 3 180° 60° 120° 0
Square 4 360° 90° 90° 2
Pentagon 5 540° 108° 72° 5
Hexagon 6 720° 120° 60° 9
Octagon 8 1080° 135° 45° 20
Decagon 10 1440° 144° 36° 35

Important fact: The sum of exterior angles of ANY convex polygon is always 360°, regardless of the number of sides.

Shortcut Methods and Tricks

Trick 1: Finding shape from diagonals If a question describes a quadrilateral by its diagonal properties, use the table above. “Diagonals bisect at right angles but aren’t equal” → Rhombus. “Diagonals are equal and bisect each other” → Rectangle.

Trick 2: Rhombus area shortcut If we know the diagonals of a rhombus, we can find the side using: side = ½√(d₁² + d₂²). This is because the diagonals form 4 right triangles with legs d₁/2 and d₂/2.

Trick 3: Finding exterior angle first For regular polygons, always find the exterior angle first (360°/n) — it’s simpler. Then interior = 180° - exterior.

Trick 4: Reverse problem — finding n from angle If given an interior angle and asked to find the polygon: exterior angle = 180° - interior angle, then n = 360° / exterior angle.

Worked Examples

Example 1: Parallelogram Area

A parallelogram has a base of 12 cm and a height of 8 cm. Find its area.

Area = base × height = 12 × 8 = 96 cm²

Note: the slant side is NOT the height! The height is the perpendicular distance between the parallel sides.

Example 2: Rhombus from Diagonals

The diagonals of a rhombus are 16 cm and 12 cm. Find the area and the side length.

Area = ½ × d₁ × d₂ = ½ × 16 × 12 = 96 cm²

Side = ½√(16² + 12²) = ½√(256 + 144) = ½√400 = ½ × 20 = 10 cm

(We used the 3-4-5 triplet here — half-diagonals are 8 and 6, so side = 10. Quick!)

Example 3: Trapezium Area

A trapezium has parallel sides of 10 cm and 16 cm, and the height between them is 9 cm. Find the area.

Area = ½ × (a + b) × h = ½ × (10 + 16) × 9 = ½ × 26 × 9 = 117 cm²

Example 4: Finding the Polygon

Each interior angle of a regular polygon is 140°. How many sides does it have?

Exterior angle = 180° - 140° = 40° Number of sides = 360° / 40° = 9 sides (nonagon)

Example 5: Number of Diagonals

How many diagonals does a decagon (10-sided polygon) have?

Diagonals = n(n - 3)/2 = 10 × 7 / 2 = 35 diagonals

Common Exam Variations

  1. “Which quadrilateral…” — identifying from properties (very common in SSC/Banking exams)
  2. Finding area from diagonals — especially rhombus and kite
  3. Perimeter of regular polygon — given one side or the interior angle
  4. Square inscribed in circle (diagonal = diameter) or circle inscribed in square (diameter = side)
  5. Angle-based problems — combining polygon angle formulas with parallel line properties

Practice Problems

Q1: The diagonals of a rhombus are 24 cm and 10 cm. Find its side and area.

Q2: Each exterior angle of a regular polygon is 30°. How many sides does it have, and how many diagonals?

Q3: A trapezium has an area of 150 cm². If the parallel sides are in the ratio 3:7 and the height is 12 cm, find the lengths of the parallel sides.


Answers

A1: Half-diagonals are 12 and 5. Side = √(12² + 5²) = √(144 + 25) = √169 = 13 cm (5-12-13 triplet!). Area = ½ × 24 × 10 = 120 cm².

A2: Sides = 360°/30° = 12 sides (dodecagon). Diagonals = 12 × 9 / 2 = 54 diagonals.

A3: Let parallel sides = 3x and 7x. Area = ½(3x + 7x) × 12 = 150. So 60x = 150, x = 2.5. Parallel sides = 7.5 cm and 17.5 cm.